Casino Games With Highest Odds – Of course not! Otherwise, all the data scientists out there would be sitting on piles of cash and the casinos would shut us down!

However, in this article we will learn how to determine if the game in the casino is good or bad. We will understand the bias of working in a casino and planning strategies to win. We will also learn how we can control the probability of bankruptcy in the casino.

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To round off the topic, I’ve added the results after using these strategies. If you can break them no strategy can prevent you from losing in the casino.

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If the answer to your second question is more than half of the first question, then you fall into the same basket as most players who go to the casino (and make a profit!).

Now here is the interesting thing, for most of the games you play in the casino, you will win money based on your chances of winning. For example: If the odds of winning at the roulette table are 1/37, you will get 37X your winnings. Therefore, the expected loss of trading in the casino is zero.

Expected profit in roulette = 1/37 * $X * 37 (amount you win if you win) – $X (amount you win) = 0

Why is our chance of winning 100% or more less than 50% but our chance of losing 100% is more than 50%. Let’s start with my last visit to the casino.

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Last week, I went to Atlantic City – the casino center of the eastern United States. Blackjack has always been my favorite game because of the misconceptions.

There are a few important things you should know about BlackJack. If you know the game, you can skip the following points:

There are some complex concepts such as insurance and distribution, which are beyond the scope of this article. So, we keep things simple.

I always thought that a dealer is restricted from opening cards until they reach 17/18, they can’t stop taking more cards. Therefore, the player has a higher chance of winning than the dealer because he has no problem. I was so excited that I was going to get it!!

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As soon as I entered the casino, I set aside $X in my “casino money” wallet, exchanged my money for chips, and within an hour, I was broke. I wasn’t done yet – hoping to get my lost money back, I paid another $2X in two rounds and finally decided that the game wasn’t as easy as I thought and that I needed to win. It was necessary to get up. information science hat.

Here are the questions, I will try to answer in this article. It can be divided into three parts:

By now, you know your cards are really bad but you either take another card and risk a bust or you take your time and let the dealer roll. Most people will tell you to stay as long as the dealer’s cards are as bad as yours – let’s test it with a simulation.

Let’s try to calculate the probability of a successful trader. I will first explain the basic functions of R and then build the trader’s arm.

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The dealer’s probability of bust is 39.6%, which is the player’s probability of winning. This means you will lose 60% of the time – is this a good strategy? We can’t answer that question until I know the chances of winning if I take one card and raise or bury my score.

Insight 1 – The probability that the dealer can be buried according to his first card (say 4) can be found in the table above (39.6% in this case).

Now we also need to bring up the player’s cards and look for a chance to win if the player has a “14” in their hand. With this additional information, we can improve our chances of winning with 2 card dealers and 1 card dealers.

The reason is that the 21st row is 100% high with only 2 cards, the 21st is a black jack. And if the dealer doesn’t have one, the player hopes to win. The player’s chance of winning at 12-16 should be equal to the dealer’s trade. This is the only way the player is going to win if he wants to stay. The merchant must open a new card if the amount is between 12-16. This fact confirms that our two samples are equivalent. To decide whether it is worth playing another card, the question asks what the player’s chance of winning would be if he chooses to play another card.

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Tip 2 – If your bankroll is more than 17 and the dealer gets a 2-6 card, the odds are in your favor. This includes regardless of relationship.

So what did you learn here? Is it better to draw cards on 8 + 6 or stay?

Here are the % success rates for each combination that can help you take action.

The cells that appear in green are where you need to select a new card. Cells shown in yellow are all cells. Cells are not visible where the player can choose at will, the difference in possibilities is negligible.

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Clue 2 – Follow the grid below to choose to stay (0) or “hit me” (1).

Doubt!!! Our success rate is much lower than our failure rate. It would be better if we flipped a coin. The big difference is that the dealer wins if the player and dealer bust. If you remove one bet, here is the win/loss.

As you can see, the dealer and the player break about 8% of the game. By making a small change, the casino ensures that we leave more than at home.

Insight 3 – Even with the best strategy, the gambler wins 41% of the time compared to the trader who wins 49%. The difference is made with a tiebreaker when the player and dealer are tied.

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This corresponds to our explosion table, which shows that the probability of the trader hitting is 28.4%. Therefore, the player and dealer will both match 28.4% * 28.4% ~ 8%.

Now we know the best playing strategy is, however, the best playing strategy can lead you to 41% winnings and 9%, leaving you with big losses. Are there any betting strategies that can save us from this puzzle?

The odds of winning in blackjack are now known. To find the best betting strategy, let’s simplify the problem. We know that the strategies that work in flipping will also work in blackjack. However, the coin toss of the event is too small to count.

Did any of the above 4 criteria surprise you? What got me thinking is that even though the average rate of leaving a casino is the same as starting one, the percentage of time a person loses is over 50%. Again, if you increase the number of games, the percentage of times a person goes bankrupt increases. Why?

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This is because we have a minimum level of $0 which is a loss, but we do not have a high level. Your lucky day, you can win as much as possible, and the casino will never stop you from saying that the casino is bankrupt. So in this game it is neutral between you and the casino, for the odd game, you and the casino have an expected value of no loss. But you have a minimum limit and the casino has no minimum limit. Well, let’s say you start with $100. If you can win you can reach $1000 or even more than $10k. But the expected value of your payout is still $100 as it was in the game. So in order to reduce the expected value, a lot of people like you have to go bankrupt. Let’s examine this theory using the functions described earlier.

It turns out that the rate of bankruptcy and marginal income seem to be correlated. This means that the more games you play, the more likely you are to become broke and rich. So, if it’s not your super-duper lucky day, you’ll miss it all. Consider 10 people P1, P2, P3, P4…. P10.

If they all start with $100, the first to lose will be P1, and the $100 will be divided into 9 more. The next in line to lose is P2 and so on. Now, you might think that P3 is on his lucky day, but if he plays enough games after going to P4, he is now on pace to earn P2.

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